[Nitro] Help creating a ObjectGraph adapter for RubyAMF
aaron smith
beingthexemplarylists at gmail.com
Tue May 22 12:12:35 EDT 2007
On 5/22/07, Jonathan Buch <john at oxyliquit.de> wrote:
> Hi,
>
> > ---For this line:
> > result = SomeModel.find() # ask if you need more help with Og queries"
> > ---Does object graph work the same way active record does? If there is
> > one result it is a object ObjectGraph::Result. And if it is multiple
> > rows it is an Array of ObjectGraph::Result. If not and it always
> > returns an array, do any of the items in the array have a special
> > class name (IE: result[0] -> ObjectGraph::Something?). That is how I
> > am finding out that this "result" is an ObjectGraph result.
>
> # Will always return an array if there are results, nil if there is no
> # result. Array contents are always .kind_of?(Og::Model)
> result = SomeModel.find()
>
> # will return return a .kind_of?(Og::Model) or nil if nothing found
> result = SomeModel.find_one()
>
> So yes, you can rely on result[0].kind_of?(Og::Model) if somethings has
> been found.
>
> > ---For column names.
> > Is there anyway I can get the column names off of the "result" object,
> > not the "SomeModel" class. As when a result is returned to me I don't
> > know about the models, just the resulting object.
>
> Ah of course. :P As you can get the class from the object. :)
>
> if result[0].kind_of?(Og::Model)
> result[0].class.serializable_attributes
> end
>
>
> Jo
>
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Sweet! That is everything I need!
#duh, i had that in the active record example.. Thanks!
if result[0].kind_of?(Og::Model)
result[0].class.serializable_attributes
Thanks a lot!
end
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