[ANN] raindrops updates (mainly for Linux users)

[Troex Nevelin]

On 03/23/2011 09:12 PM, Troex Nevelin wrote:
> For example we know that an average response time is 0.15 sec, than if 
> our mean queue is 32 requests, each request will be served in 
> (32+1)*0.15=4.95 seconds.

Probably it should be:
((mean_queue + 1) * avg_response_time) / workers 

so in my example it would be:
((32 + 1) * 0.15) / 8 =~ 0.62 sec